3.1.55 \(\int \frac {(a+b \tan (c+d \sqrt [3]{x}))^2}{x} \, dx\) [55]

Optimal. Leaf size=23 \[ \text {Int}\left (\frac {\left (a+b \tan \left (c+d \sqrt [3]{x}\right )\right )^2}{x},x\right ) \]

[Out]

Unintegrable((a+b*tan(c+d*x^(1/3)))^2/x,x)

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Rubi [A]
time = 0.01, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {\left (a+b \tan \left (c+d \sqrt [3]{x}\right )\right )^2}{x} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Int[(a + b*Tan[c + d*x^(1/3)])^2/x,x]

[Out]

Defer[Int][(a + b*Tan[c + d*x^(1/3)])^2/x, x]

Rubi steps

\begin {align*} \int \frac {\left (a+b \tan \left (c+d \sqrt [3]{x}\right )\right )^2}{x} \, dx &=\int \frac {\left (a+b \tan \left (c+d \sqrt [3]{x}\right )\right )^2}{x} \, dx\\ \end {align*}

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Mathematica [A]
time = 17.08, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (a+b \tan \left (c+d \sqrt [3]{x}\right )\right )^2}{x} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Integrate[(a + b*Tan[c + d*x^(1/3)])^2/x,x]

[Out]

Integrate[(a + b*Tan[c + d*x^(1/3)])^2/x, x]

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Maple [A]
time = 0.82, size = 0, normalized size = 0.00 \[\int \frac {\left (a +b \tan \left (c +d \,x^{\frac {1}{3}}\right )\right )^{2}}{x}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a+b*tan(c+d*x^(1/3)))^2/x,x)

[Out]

int((a+b*tan(c+d*x^(1/3)))^2/x,x)

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Maxima [A]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*tan(c+d*x^(1/3)))^2/x,x, algorithm="maxima")

[Out]

(6*b^2*x^(2/3)*sin(2*d*x^(1/3) + 2*c) + (d*cos(2*d*x^(1/3) + 2*c)^2 + d*sin(2*d*x^(1/3) + 2*c)^2 + 2*d*cos(2*d
*x^(1/3) + 2*c) + d)*x*integrate(2*(2*a*b*d*x*sin(2*d*x^(1/3) + 2*c) + b^2*x^(2/3)*sin(2*d*x^(1/3) + 2*c))/((d
*cos(2*d*x^(1/3) + 2*c)^2 + d*sin(2*d*x^(1/3) + 2*c)^2 + 2*d*cos(2*d*x^(1/3) + 2*c) + d)*x^2), x) + ((a^2 - b^
2)*d*cos(2*d*x^(1/3) + 2*c)^2 + (a^2 - b^2)*d*sin(2*d*x^(1/3) + 2*c)^2 + 2*(a^2 - b^2)*d*cos(2*d*x^(1/3) + 2*c
) + (a^2 - b^2)*d)*x*log(x))/((d*cos(2*d*x^(1/3) + 2*c)^2 + d*sin(2*d*x^(1/3) + 2*c)^2 + 2*d*cos(2*d*x^(1/3) +
2*c) + d)*x)

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Fricas [A]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*tan(c+d*x^(1/3)))^2/x,x, algorithm="fricas")

[Out]

integral((b^2*tan(d*x^(1/3) + c)^2 + 2*a*b*tan(d*x^(1/3) + c) + a^2)/x, x)

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Sympy [A]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (a + b \tan {\left (c + d \sqrt [3]{x} \right )}\right )^{2}}{x}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*tan(c+d*x**(1/3)))**2/x,x)

[Out]

Integral((a + b*tan(c + d*x**(1/3)))**2/x, x)

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Giac [A]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*tan(c+d*x^(1/3)))^2/x,x, algorithm="giac")

[Out]

integrate((b*tan(d*x^(1/3) + c) + a)^2/x, x)

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Mupad [A]
time = 0.00, size = -1, normalized size = -0.04 \begin {gather*} \int \frac {{\left (a+b\,\mathrm {tan}\left (c+d\,x^{1/3}\right )\right )}^2}{x} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b*tan(c + d*x^(1/3)))^2/x,x)

[Out]

int((a + b*tan(c + d*x^(1/3)))^2/x, x)

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